编写SQL查询,报告第一次登录的第二天再次登录的播放机的分数,将其四舍五入到小数点后的2位。换句话说,您需要计算从第一个登录日期开始至少连续两天登录的玩家数量,然后将该数字除以玩家总数。查询结果格式如下所示。player with id 1 logged back in after the first day he had logged in so the answer is 1/3 = 0.33
使用此查询时tp.all_
我希望使用php在mysql中交替选择行,$result=mysql_query("select * from marker1 where date='$maxdate' and time BETWEEN '$mintime' AND'$maxtime' and imei_no='$vehicle_imei_no1'")or die(mysql_error());这是我的查询</e