SELECT IF((SELECT COUNT(id) FROM table WHERE id = 1) = 0, 1, <nothing_to_happen>) AS Available+---------++---------++---------+SELECT id FROM table WHERE
我有一个问题如下:
$sult = mysql_query("select * from stories where `categ` = 'businessnews' and `stryid`='".mysql_query("SELECT * FROM comments WHERE `comto`='".mysql_query("select * from stories where `categ`
我正在尝试限制从JOIN语句检索的行数。REFERENCES `conversation` (`id`)我想从涉及特定用户的20个会话中获得最后N条消息(假设id为42的会话)SELECT`creator_id` SELECT * FROM `message` ORDER BY `date` DESCLIMIT 20;
因为MySQL