我在同一个PHP文件/页面中有两个查询,当它们像这样工作时,我就会得到结果。
$query1 = mysqli_query($link, "SELECT * FROM tableA");
$restult1= mysqli_fetch_assoc($query1);
$query2= mysqli_query ($link,"SELECT COUNT(id) AS total FROM tableB");
while ($row = mysqli_fetch_assoc($query2)){
echo '<option value=
<?php
require 'database.php';
$msg= "Quntity is less than 10";
$numResults = mysqli_query($conn, "select COUNT(*) as `count` from item where item_quantity <10");
$row = mysqli_fetch_array($numResults);
$count = $row['count'];
if ($co
我有下面的代码来显示数字如果记录在表中,它总是显示1,即使我将列名更改为另一个列名;
但是,工作台中的相同查询会显示正确的记录数。见截图;
$con = @mysqli_connect( "localhost:3306", "root", "P@ssw0rd", "classicmodels" ) or die ("Couldn't connect to server");
//get total number of records
$query = "SELECT cou
我正在尝试在数据库中保留最近的10个条目,并删除较旧的条目。我尝试过DELETE FROM people ORDER BY id DESC LIMIT $excess,但它只删除了前10个条目。
$query = "SELECT * FROM people";
$result = mysqli_query($conn, $query);
$count = mysqli_num_rows($result);
if ($count > 10) {
$excess = $count - 10;
$query = "DELETE FROM people W
我有以下代码,我想一次更新多行,但不工作。有人能帮我吗?这是显示未初始化字符串偏移量,我是怎么了?我有以下代码,我想一次更新多行,但不工作。有人能帮我吗?这是显示未初始化字符串偏移量,我是怎么了?
$con = mysqli_connect("localhost","root","","test");
$con->set_charset("utf8");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to con
我试图对从数据库中检索到的数据执行一些计算,但是每次我运行这段代码时,都会得到NAN作为输出。
function calculateNPS()
{
$queryTotal = "SELECT count(*) as total FROM message";
$resullTotal = mysqli_query($link ,$queryTotal);
$queryYes= "SELECT count(visit) as yes FROM message WHERE visit='Yes'
我在php代码中有查询
$dbc = mysqli_connect('localhost', 'root','', 'delivery')
or die('Error connecting to MySQL server.');
$count = "SELECT MAX(id_pelanggan) FROM pelanggan";
$result = mysqli_query($dbc, $count)
or die
我有以下SQL函数,并且我已经删除了mysqli_stmt_bind_result中的$row。
//get the user number per month
public function chartwaitinguservsproduct(){
$stmt = mysqli_prepare($this->connection,
"select
(Select COUNT(*) from reusematching.waitinglist_product) as COUNTP,
我对PHP和MySQL还是个新手,我在不同的地方读过很多东西,我设法把这个脚本拼凑在一起,不幸的是,输出结果并不完全符合我的预期,我得到了很多:
Buffer Status 2H: Notice: Undefined variable: row in /var/www/secretbit/allbuff.php on line 53 0 records. <br />
Buffer Status TC: Notice: Undefined variable: row in /var/www/secretbit/allbuff.php on line 54 0 records. &l
我需要一些帮助设置一个php脚本,将重定向用户,如果他们的IP和时间戳是旧的超过20分钟。
也许有一种更好的方法可以做到这一点。我让页面请求工作,这是转储IP地址和Datetime。这是我到目前为止用验证拼凑起来的:
// Check IP address and Time Stamp and block access if needed
$query = "SELECT count(`id`) AS 'count'
FROM `visits`
WHERE
`client_ip` = '".mysqli
我无法获得第一次查询的所有用户id来使用这些id进行第二次查询。
当我计算第一次查询时,它的显示总是1。这意味着它只能从sql中得到一个结果。但是我想,使用我的第一个查询的所有id到第二个查询。
请问我哪里错了?
我的代码:
$a = $session->username;
$b = $session->pname;
if (empty($b)) $b = $a;
$g = mysqli_query($dbh,"SELECT id FROM update WHERE `from_id`='$b' OR `to_id`='".$session-
$result = $conn->query($sql);
echo $result->num_rows; //2 is value produced
但
$tagResult = mysqli_fetch_array($result,MYSQLI_NUM);
echo count($tagResult); //1 is the value produced
它不是应该产生相同数量的值吗?
我使用准备好的语句执行了一个查询,现在我想在while循环中执行另一个查询。但它给了我一个错误,即Commands out of sync; you can't run this command now。如何解决这个问题? <?php
$query = "SELECT post_id, post_title, post_author, post_date, post_image, post_content, post_tags FROM posts WHERE post_status = ? LIMIT ?, ?";
$stmt = mysqli_prepare
这是我第一次使用MVC,并且我已经阅读了代码触发器的文档。但我似乎不能正确地理解这个问题:
$score = $_POST['time'];
$sql = "SELECT COUNT(score) as c FROM highscores WHERE score < '$score' ORDER BY score ASC LIMIT 10";
$result = mysqli_query($con, $sql);
$count = mysqli_fetch_object($result)->c;
if(!is_null($count)
如何编写开关柜的代码,给出x和y的数值?X和y在一个数组中。数组中的数据来自数据库。 <?php
$main_link = mysqli_connect('localhost', 'root', '','WMYC');
$a1 = mysqli_fetch_array(mysqli_query($main_link, "SELECT * FROM teams WHERE team='t1' AND round='r1'"));