conversion from ‘int*’ to ‘int’void findNeighbours(int x, int y, int xSIZE, int ySIZE, list<int>& neighboursn[2]={x-1,y}; int s[2]={x+1,y}; switch(x){ case xSIZE-1: {neigh
假设我有一个类似list map的矩阵,其中存储了一些对象。现在,按照list的工作方式,map[x-1]在map[elemInList-1]中产生。除了手动设置x的边界(如if x < 0 )之外,还有其他解决办法吗?for x in range(row): try: map[x][y].neighbors.append(map[x][y - 1])
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: non-empty list of potential neighbours -> narrowed list of validated neighbours that are in the grid(define (neighbours-in-grid (neighbours (random-cell a-maze)))
(cond [(< 0 (first neighbours) > grid-size) (remove (first neighbours)
我需要在一维封闭场上找到细胞的近邻邻居我的邻居守则neighbours l = concat [[[last l, headl, last $ take 2 l]], neighbours' l, [[l !!(length l - 2), last l, head l]]] where neighbours' (a