SELECT MIN (snap_id) AS FIRST_SNAP, MIN (BEGIN_INTERVAL_TIME) AS FIRST_QUERY, max(end_interval_time) - min(begin_interval_time) as "TIME_ELAPSED"ORDER BY snap_id;
2931 3103 5
我正试图收集一周和一个月的所有当前日子。这应该很容易,但只要我搜索,我就找不到解决办法。例如,把今天当作一天,我需要的结果是这样的:$daysInMonth = [1,2,3,4,5,6,7,...,28];//Note here that are febrary, and need to return 28, not 31 $weekStartDate = Carbon::now()->startOfWeek();
$month
此外,在$leeft变量中还显示了所剩的天数、小时、分钟数。差额(购买日+5天)-日期require_once "global.php";
SELECThave_special_relative"]=> int(0) }
Fatal error: Call to a member function format() on integer in /stackover