我有一个可以同时使用MySQL数据库和ODBC DB连接(QODBC到QuickBooks)的PHP脚本。设置如下:
Retrieve rows from MySQL database
Begin MySQL transaction:
Loop through rows
Process data
MySQL Insert/Update
MySQL Update
QODBC Selects/Inserts
End Loop
MySQL Delete
Commit Transaction
问题是,如果QODBC部分中有错误,那么到那时为止的MySQL
我的网站有PHP命令:
mysql_query("SELECT * FROM users WHERE id=" . $_GET["id"]) or die(mysql_error());
当我输入URL
http://example.com/index.php?id=1;%20UPDATE%20users%20SET%20password=123%20WHERE%20id=1
我得到以下错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL
将MySQL中的用户auth插件更改为'sha256_password':
ALTER USER 'user'@'N.N.N.N' IDENTIFIED WITH 'sha256_password' BY 'password';
test.php
#!/usr/bin/env php
<?php
$my = new mysqli('M.M.M.M', 'user', 'password');
echo "OK\n";
$my->close(
MySQL推迟了以下错误:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE IF NOT EXISTS `badips` ( `id` int(10) NOT NULL auto_increment, ' at line 2
当我运行以下PHP时:
if (file_exists("../login/includes/conf
这两个PHP MySQL查询是有效的。
mysql_query("DELETE FROM videos WHERE id='10';");
mysql_query("DELETE FROM comments WHERE videoId='10';");
由于与后一个DELETE操作相关的MySQL语法错误,该单个查询失败。
mysql_query("DELETE FROM videos WHERE id='10';DELETE FROM comments WHERE videoId='10'
当我在mysql中测试这个查询时,它很好,但是当我在php中运行它时,我一直得到这个错误。
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT *, (@rownum := @rownum + 1) AS rank FROM ( SELECT *, (totalWins+(total' at line 1
这是我的php代码。
<
嘿,我正在尝试使用unlink();函数让我的网站删除一个文件。但当我尝试时,它会出现这样的情况:
Warning: unlink() [function.unlink]: cURL does not allow unlinking in /home/nzcraftn/public_html/filenz/user/delete.php on line 18
Warning: Cannot modify header information - headers already sent by (output started at /home/nzcraftn/public_html/file
当我手动检查phpmyadmin时,我的sql查询运行良好,但当我尝试通过php mysql_query处理它时,会抛出一个语法错误。如何解决这个问题?
错误消息:
Invalid query:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO scores( user_id ) VALUES (LAST_INSERT_ID( ))' a
我正在尝试使用PHP脚本执行MySQL事件。当我在数据库中使用事件调用"joy“执行PHP脚本时,我只是尝试将两个数据字段插入到表中,但是当我调用该事件时,表中没有插入任何数据。
我的PHP脚本是:
<?php
include("connect.php");
$insertquery="CREATE EVENT joy
ON SCHEDULE AT CURRENT_TIMESTAMP + INTERVAL 3 MINUTE
DO
BEGIN
insert into tri (name,email) value
我在php中有以下脚本来登录mysql
$db_host="localhost";
$db_user="root";
$db_pass="123";
$dbc=mysql_connect($db_host,$db_user,$db_pass) OR DIE (mysql_error());
$dbs=mysql_select_db($db_name) OR DIE (mysql_error());
这个脚本工作得很好,现在我重新安装了操作系统,现在我有Windows7、iis7和PHP5.3.2& mysql
我正在尝试一种SQL注入:
http://localhost/test/mysql.php?uid=1;%20DROP%20TABLE%20test
这个URL应该等于以下语句:
SELECT username FROM test WHERE userid=1; DROP TABLE test
但是,当我打开这个URL时,会弹出一个错误:
Error:You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax t
最近,我开始使用一个继承的Drupal 8网站,我正试图在Mac (塞拉利昂)上运行该网站,但每次尝试运行drush或访问该网站时,我都会使用堆栈跟踪来获得此错误。任何关于导致这一问题的原因以及如何修复的提示都将不胜感激。
jc@~/Development/Sites/example-website/web $ drush
PDOException: SQLSTATE[42000]: Syntax error or access violation: 1231 Variable 'sql_mode' can't be set to the value of