见鬼,我在ajax中发送了3个请求,我的one服务将返回给我3个成功消息,我只想显示一个。.done(function(shipdata) { var msgerror = ship.filter('#alert'); $("#ship-modal-data p").append("code postal, ville destinataire est erronée.&#
我在MySql中有一个搜索问题。以下是目前为止的代码:)
$sqlsearch = mysql_query("SELECT * FROM Cars WHERE zipcode LIKE '%$ziprangesub%' AND numberofpeople>='$numberofpeople' AND '$date' in ('date1','date2','date3',&