我正在开发一个网站,用户可以注册和访问他们的帐户,当用户连接时,我使用序列化和base64编码将用户对象保存在cookie中。它运行得很好,突然PHP脚本不想创建cookie。我的PHP脚本是:
/**
* Function that creates a cookie from an User object
* @param User $user User object to be stored in the cookie
* @param int $timeout Lifetime of the cookie (0 if should be destroyed when the nav
我得到的错误是
请求失败:在索引42: http:/10.0.2.2:8080/webservice2.php?json={\"UserName\":1,\“FullName\”:2}查询中的java.lang.IllegalArgumentException:非法参数
main.java
package com.hamdyghanem.httprequest;
import java.*(etc etc)
public class Main extends Activity {
/** Called when the activity is first creat
我正在使用Symfony包“symfony/序列化器”序列化实体。
我能够在没有问题的情况下将我的实体编码成json,但是我在反序列化它并将它带回原来的形式时遇到了问题。我所收到的错误是;
Could not denormalize object of type AppBundle:Entity, no supporting normalizer found.
DefaultController.php
//Create Entity to Serialize
$entity = new Entity();
$entity->setId(1);
$enti
Class User{
public $id;
public $username;
public $password;
public $email;
public $steam;
public $donator;
public $active;
public function __construct($username, $email, $password, $id, $active, $donator, $steam){
$this->id = $id;
$this->username = $username;
$this->password
我需要创建自定义jackson泛型类型化bean反序列化程序。T是实现IEntity的bean。
public interface IEntity {
public int getId();
}
@JsonDeserialize(using = RestLoaderRequestDeserializer.class)
@Produces(MediaType.APPLICATION_JSON)
public class RestLoaderRequest<T extends IEntity> Serializable {
private T entity; // e
我有一个对象,我想在程序的一部分用属性序列化它,但不想在另一部分序列化。我还有一个广泛定制的ObjectMapper,用于这两种序列化。我的第一个想法是在显示属性时使用Mixin进行调整,但似乎只能将其放在ObjectMapper上,而不能放在由ObjectMapper返回的读取器上。基本上,我希望能够编写的代码如下所示。
ObjectMapper myMapper = new ObjectMapper(); // in reality there is a lot of customization
Foo foo = myMapper.reader().withMixin(Foo.class