这段代码可以工作
<?php
for ($x = 0; $x <= 10; $x++) {
echo "The number is: $x <br>";
}
?>
但是如果不是使用“<=”,而是简单地使用“=”php进入一个无限循环,即超时
<?php
for ($x = 0; $x = 10; $x++) {
echo "The number is: $x <br>";
}
?>
这是预期的行为吗?
在本地主机上运行我的代码时,include命令出现了问题。 下面是我的代码: <?php
$res = 2; // this also can be change to any number. it is based on user input, but for simply the problem i make it to be set manually
If ($res =1,){
$open = include ("weekend.php");
}
else{
$open = include ("weekday.php");
在代码中
<?php
if(isset($_POST['submit'])){
$post_image=$_FILES['post_image']['name'];
$post_image_tmp=$_FILES['post_image']['tmp_name'];
if($post_image='' ){
echo "<script> alert ('please fill in all fields')</scri
我有一个问题,这个php代码的login.When我登录为“雇主”一切都是ok.But当我作为雇员登录时,它应该加载一个不同的page.It总是把它当作我已经登录为“雇主”。
<?php
session_start();
require_once('connection.php');
//Connect to server
$link = mysql_connect($host, $user, $pw) or die(mysql_error());
//Select the database
mysql_select_db ($db)
我已经安装了Redis、Php和Php,现在当我运行下面的程序时,我得到了
<?php
//Connecting to Redis server on localhost
$redis = new Redis();
$redis->connect('127.0.0.1', 6379);
echo "Connection to server sucessfully";
//check whether server is running or not
echo "Server is running: "
我看到了以下代码片段:
<?php
if(!empty($_POST)): // case I: what is the usage of the :
if(isset($_POST['num']) && $_POST['num'] != ''):
$num = (int)$_POST['num'];
....
if($rows == 0):
echo 'No';
else: // case II: what is usage of :
echo $rows.'Yes'
有人能告诉我为什么下面的东西不起作用吗?它只重定向到第一个位置,即使我选择不同的单选按钮。
PHP:
if (isset($_POST['submit'])) {
if (!empty($_POST['electronics'])) {
if ($_POST['electronics'] = "camera") {
header("location: camera.php");
exit();
}
if ($