UPDATE 'module_tests' SET 'tests_content' = REPLACE('tests_content', '<a onclick=', '<a class="dic" onclick=');
当我试图在phpmysql中运行top query时,它给出了以下错误。有人能告诉我这是什么原因吗?
#1064 - You have an error in your SQL syntax; check the manual that corresponds to
我是第一次来到Talend Studio。我设计了一个将数据从phpmysql转换到phpMysql本身的工作。出现以下错误:
java.net.ConnectException: connect: Address is invalid on local machine, or port is not valid on remote machine
......
Exception in component tMysqlOutput_1
java.lang.NullPointerException
at routines.system.RunStat.sendMessages(RunStat.
我正在尝试使用下面的代码为我的wordpress站点添加/更新所有帖子的自定义字段值……在phpmysql中
INSERT INTO wp_postmeta (post_id, meta_key, meta_value)
SELECT ID AS post_id, 'views'
AS meta_key 'RAND(6)*20' AS meta_value
FROM wp_posts WHERE ID NOT IN
(SELECT post_id FROM wp_postmeta WHERE meta_key = 'views')
`` AND
我正在制作一个“你应该学习什么语言”的网站,但更复杂的是,我不知道为什么,但当我选中复选框时,它们不是真的,但当我现在重新加载页面时,它们是真的 if (document.getElementById("langage1").checked) {
html = true;
}
if (document.getElementById("langage2").checked) {
phpmysql = true;
}
if (document.getElementById("langage3").checked) {
js = t
编辑:在我从最初的文章中得到反馈后,我修改了文本以澄清我的问题.
我有以下查询(伪代码):
$conn = mysql_connect('localhost', 'mysql_user', 'mysql_password');
mysql_query("SET NAMES 'utf8'; COLLATE='utf8_danish_ci';");
mysql_query("SELECT id FROM myTable WHERE name = 'Fióre`s måløye'
我正在尝试使用phpmysql进行全文搜索,但它在mysql_num_rows中显示错误,你能告诉我错误是什么吗?我创建了全文索引,并更改了表引擎。
$search=mysql_real_escape_string($_POST['name']);
$sql="SELECT * FROM article WHERE MATCH(title, comment) AGAINST ('.$search.')";
$query = mysql_query($sql);
//Check if any results were ret
我正在测试一个简单的PHP-MySQL脚本,它将从表中删除一条记录。奇怪的是在这段代码中:
// Check if the form has been submitted:
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
if ($_POST['sure'] == 'Yes') { // Delete the record.
// Make the query:
$q = "DELETE FROM users WHERE user_id=$
如何用自己的服务器端数据填充Google Chart API,也就是在PHPMySQL中。
目前我有以下数据:
function drawChart()
{
// Create the data table.
var data = new google.visualization.DataTable();
data.addColumn('string', 'City');
data.addColumn('number', 'Number of Crimes');
data.addRows([
[