line 2, in <module> File "C:\Users\user\AppData\Local.create_polygon import create_polygon
File "C:\Users\user\AppData\Local\Programs\Python\Python37\lib\sphericalpolygon\polygonclasses\s
# Check if the point lies within polygon, if true, get the market.for key, val in geom_dict.items():
polygon = Polygon(val)", line 76, in market_Lookup File "/Users/
我使用python,我在地图上定义了一个多边形的纬度和经度。我的目标是检查一个坐标的泛型点P x,y是否在这样的多边形内。下面是我到目前为止编写的代码:v0 = [7.5, -2.5] x, y = -6, 5 # x = Lat, y = Lon
## START MODIFYING FROM HERE; DO NOT MODIFY POLYGON
我试图在python中自动化这一部分代码(代码显示为2个多边形,我试图对10000个多边形进行同样的操作)。任何关于如何使用for循环或您推荐的最快方式来实现这一点的想法。### Polygon 1 point = Point((row['X']), (row['Y']))datacopy['InPolygon1'] = d