我在下面提到了SQL,结果得到了下面提到的dataset。但我只想显示一个打开状态记录,其中有最小日期。 o.svc_ord_stat_nm AS SVC_ORD_STAT_NM,FROM A o inner join B t on t.ticket=o.notif_nbr
and o.svc_ord_nbr in ('021519_574819','110714
() over (partition by dept order by DECODE(sum(calls),0,0,sum(handletime) / sum(calls)) DESC) as YTD_P_RANK_ALL_LOCATIONS,PERCENT_RANK() over (partition by dept, location by DECODE(sum(calls),0,0,sum(handletime) / sum(calls)) DESC) as Y
(PARTITION BY tbl2.lot) DESC, Sum(tbl1.qtd) DESC, tbl2.lot, tbl1.defect, tbl1.descSELECT * SELECT DENSE_RANK() OVER (ORDER BY Sum(Sum(tbl1.qtd)) OVER (PARTITION(PARTITION BY tbl2.lot) DESC, Sum(tbl1.
这是当前的查询,结果有6列(还请参阅所附的屏幕快照): value, count(*) over (partition by amino_acid(partition by sample_name order by rank desc) as rank,
sum(value) over (partition by amino_acidby rank desc)
我疲倦地组合了RANK,ROW_NUMBER等,但没有运气。() OVER ( PARTITION BY direction ORDER BY time) + ROW_NUMBER() OVER ( ORDER BY time DESC) AS rnk-- DENSE_RANK() OVER ( PARTITION BY seq ORDER BY time),
-- ROW_NUMBER() OVER ( ORDER BY seq, timeD
使用SQL Server Management Studio v17.9.1 我试图根据站点和区域的日期对一些数据进行排名/排序/分组,但我很难弄清楚,不是按字母顺序对区域进行排名,而是按照出现的最早日期进行排名。 以下是我掌握的数据: Site | Area | Space | DateDCG X 5 04/02/2020 11:47
DCG X 12 10/02