stringg <- c("You are\ngoing to learn 3 things, the first one is not to extract, and\n2 and 3 are simply digits.", "....", "....",....)
在R中,我希望找到以“”结尾的所有listitem/字符串。在这个点之后,我想给它加上一个$符号。
grep("\\.$", stringg , value = TRUE) # this gives me the string from list which
我有字段输入与多数据选择,多数据选择输入日期在字段中,如:2016-10-02,2016-10-13,2016-10-25。如何验证所有的日期或一个,也许我可以使用数组regexp验证器,如果存在?
$element_edit->addValidator ('regex', false, array(
'pattern'=>'/^\d{4}-\d{2}-\d{2}$/',//for only one
'messages'=>array(
'regexNotMatch'
好的,所以我的任务是使用Lisp表达式:
'(A B C D)
并将其转化为
'(D C B A)
在Java中。要做到这一点,我有以下代码:
String[] items = input.split(" |\\(|\\)|'");
int y = 0;
for (String x : items){ //this part is purely for debugging
System.out.println(y + " " + x);
y++;
}
所以它用一个空格,(,)和‘来分割它。我应该得到的输出是
0 A
1 B
我是非常非常n00b在正则表达式,我正在努力学习,但没有成功:)。
所以我有以下文件名:myFile.8.9.6-x64.txt或myFile.8.9.6-x86.txt
因此,我希望创建一个正则表达式,以便将文件名中的x64或x86字符串匹配为:
var regexp = new RegExp(/[x_X][8][6]|[x][6][4]$/);
console.log(regexp.test("myFile.8.9.6-x64.txt")); //returns false instead of true
那么,我的错误在哪里?
我有一个格式错误的CSV文件,它有两列: Text,Value
值要么为1,要么为0,但有些线条格式错误,跨越两行:
1. "This line is fine, but there are some that are not like this",0
2. "Another good line",1
4. "Oh, I'm so bad!!
5. I spanned two lines!",0
6. "Why did you break me? FileHelpers can't read two lines!!"
如何对输入的1到3位数字进行模式匹配验证。我在下面试过了,但没有用。
<input type="text" title="FOO should be a 3 Digit Number Only" pattern="[\d]{3}" id="uid" name="foo<?php echo $i+1;?>" placeholder="Enter FOO" placeholder="FOO" required="'required'" m
如何编写正则表达式来删除某个特定制表符后面的句子?
例如,我在richtextbox中的文本
a 00001740 0.125 0 able#1 (usually followed by `to') having the necessary means or skill or know-how or authority to do something; "able to swim"; "she was able to program her computer"; "we were at last able to buy a c
嗨,我一直在尝试使用Java学习RegExpresions,我还处于初级阶段,我想开始一个小程序,它被赋予一个字符串,并输出音节标签split.This是我到目前为止所得到的:
String mama = "mama";
Pattern vcv = Pattern.compile("([aeiou][bcdfghjklmnpqrstvwxyz][aeiou])");
Matcher matcher = vcv.matcher(mama);
if(matcher){
// the result of this should b