Developer David JacksonJohn Smith Patricia Salomon36656Analyst Josh AdkinsJohn Smith PatriciaSalomon78568 Programmer Rick Tyler
Jody Melito Ana Carlisle 67
在科特林,给他上了几门课: open fun sayHi() = "hi"以及需要子类扩展A的特征T: override fun sayHi() = super.sayHi() + " John"人们会期望T.sayHi能够调用super.sayHi()或更显式的super<A>.sayHi(),因为所有类型的信息都在那里,但是它会生成Superclass is not accessible from trait。我如何从特征内