scala宏如何将`HList`转换为函数参数

import shapeless._
import shapeless.ops.hlist.ToTraversable

import scala.reflect.macros.blackbox

object HListToArgs {
  def hlistToArgs[A <: HList, R](hlist: A)(implicit tt: ToTraversable.Aux[A, List, Any], ev: R <:< AnyRef): List[AnyRef] = {
    hlist.toList.asInstanceOf[List[AnyRef]]
  }

  def hlistToArgsMacro(c: blackbox.Context)(hlist: c.Expr[HList]): c.Expr[List[AnyRef]] = {
    import c.universe._

    val hlistType = c.weakTypeOf[HList]
    val toTraversableType = typeOf[ToTraversable.type].typeSymbol
    val auxType = typeOf[ToTraversable.Aux[_, _, _]].typeSymbol

    val ttTree = Select(Ident(toTraversableType), TermName("apply")).setType(NullaryMethodType(NoType))
    val evTree = Select(Ident(typeOf[R <:< AnyRef].typeSymbol.companion), TermName("apply")).setType(NullaryMethodType(NoType))

    val result = q"$hlist.toList.asInstanceOf[List[AnyRef]]"

    c.Expr[List[AnyRef]](result)
  }
}

import shapeless._

val hlist = 1 :: "hello" :: true :: HNil
val args = HListToArgs.hlistToArgs(hlist)
println(args) // 输出: List(1, hello, true)