我对ZF2中的Select有问题。
Class One {
function search(){
$select = new Select();
$this->conditions($select);
$select->join(['t'=>'table'],'t.id = other_table.table_id',[]);
}
function conditions(select $select){
$select->join(['t'=>'
我有一个通过DI使用\Zend\Db\TableGateway\TableGateway的映射器。我模仿过它,因为单元test.Here是测试:
class EMSMapperTest extends PHPUnit_Framework_TestCase
{
public function testFetchAllReturnsAllScheduledBlocks()
{
$resultSet = new ResultSet();
$mockTableGateway = $this->getMock(
'
是否有语法允许将索引器作为Select(Func<T,TResult> selector)选择器传递?例如,对于使用索引器的以下代码,是否有速记(即没有‘箭头’):
// full version using indexer
collection.Select(key => dictionary[key]);
与任何其他成员函数的方式相同?例如:
// full
collection.Select(key => dictionary.ContainsKey(key));
// shorthand
collection.Select(dictionary.Contains
我有以下SQL表达式:
SELECT SS_ITEM_SK AS POP_ITEM_SK
FROM (SELECT SS_ITEM_SK
FROM (SELECT SS_ITEM_SK,(ITEM_SOLD-ITEM_RETURNED) AS TOT_SOLD_QTY FROM (SELECT SS_ITEM_SK,COUNT(SS_ITEM_SK) AS ITEM_SOLD,COUNT(SR_ITEM_SK) AS ITEM_RETURNED FROM STORE_SALES1 right outer join STORE_RETURNS1 on SS_TICKET_NUMBER = S
下面的代码有问题。
public IEnumerable<BillingConfiguration> GetBillingConfigurationsForAccount(int accountId, DateTime? effectiveDate)
{
var result = new List<BillingConfiguration>();
var accountIds = new List<int>();
var billingGroupIds = new List<int>();
假设我希望使用自定义方法在数组中选择元素。为了论证起见,我将使用奇偶。
一般来说,是否有好的做法/建议在使用
class Integer # Adding method to the Integer class
def my_fancy_select
self % 2 == 0
end
end
puts my_array.select(&:my_fancy_select)
和
def my_fancy_select(i) # could be a private method
i % 2 == 0
end
puts my_array.select{|i| my_
如何将这些语句组合到一条SQL语句中?
select city from station where city like 'a%';
select city from station where city like 'e%';
select city from station where city like 'i%';
select city from station where city like 'o%';
select city from station where city like 'u%';