= superstars.id GROUP by superstar01 Order by COUNT(superstar01) desc;
SELECT superstars.name,COUNT(superstar02) FROM smackdown_teams JOIN superstars on smackdown_teams.superstar02 = superstars.id GROUPby superstar02 Order by COUNT(superstar02) d
Create Table SuperstarSuperstar_ID Int Not Null Primary Key Identity (100,1), SuperStar_Weight Varchar(50) Not Null, Former_Holder Int Foreign Key Refe
我尝试用Python在循环中将一个查询传递给sql: for i in superstar.iloc[:, 0]:
DROP TABLE IF EXISTS superstar_fwdPlusbwd_{i}; \
CREATE TABLE superstar_fwdPlusbwd_{i}manual that corresponds to your MySQL server version for t
brothers', 'legend of zelda breath of the wild',
'kirby superstar,是否可以打印super mario brothers;如果用户输入zelda,可以打印legend of zelda breath of the wild;如果用户输入star,可以打印kirby superstar