tic tac toe python-乌龟x和o交替

# 定义一个3x3的空棋盘
board = [[' ' for _ in range(3)] for _ in range(3)]

# 定义两个玩家的标记
player1 = 'x'
player2 = 'o'

# 定义当前玩家，默认为玩家1
current_player = player1

# 打印棋盘函数
def print_board():
    for row in board:
        print('|'.join(row))
        print('-' * 5)

# 判断是否有玩家获胜函数
def check_win(player):
    # 检查水平线
    for row in board:
        if row.count(player) == 3:
            return True

    # 检查垂直线
    for col in range(3):
        if [board[row][col] for row in range(3)].count(player) == 3:
            return True

    # 检查对角线
    if board[0][0] == board[1][1] == board[2][2] == player:
        return True
    if board[0][2] == board[1][1] == board[2][0] == player:
        return True

    return False

# 游戏主循环
while True:
    print_board()

    # 获取玩家输入的坐标
    row = int(input("请输入行号（0-2）："))
    col = int(input("请输入列号（0-2）："))

    # 检查坐标是否合法
    if row < 0 or row > 2 or col < 0 or col > 2 or board[row][col] != ' ':
        print("无效的坐标，请重新输入！")
        continue

    # 在棋盘上放置玩家的标记
    board[row][col] = current_player

    # 判断当前玩家是否获胜
    if check_win(current_player):
        print_board()
        print("玩家", current_player, "获胜！")
        break

    # 判断是否平局
    if all([cell != ' ' for row in board for cell in row]):
        print_board()
        print("平局！")
        break

    # 切换到下一个玩家
    current_player = player2 if current_player == player1 else player1