By Name;
查询运行良好,但是当我添加了一个UNION时,如下所示: xmlagg(xmlelement( "Species",xmlforest(case when Tail is not null then Tail else null end "Trait"))) xmlagg(xmlelement( "Species",
下面是我的查询示例:Select Top 5 JobID From Jobs Where JobTypeID = 1 Order By JobID DESCSelect Top 5 JobID From Jobs Where JobTypeID = 2 Order By JobID DESCSelect Top 5 JobIDFrom Jobs Where JobTypeID = 3 Order
我真的厌倦了access和它奇怪的SQL语法,我浏览了谷歌和StackOverflow,我找到了提示,但我无法让我的大查询工作……我只是有多个左外连接,我不能安排在括号内,让它被这个该死的访问接受…SELECT concat,ORDER_NUM, ConTY4 AS CT, ConValue4 AS CV FROM GEN_ITEMS UNIONALLSELECT concat,ORD
SELECT ID,Bill_typeID,Cust_ID,Name,Reg_date,Account_Number,Amount,status FROM Cust_Bill_Reg_M_Tbl SELECT ID,Bill_typeID,Cust_ID,Name,Reg_date,Account_Number,Amount,status FROM Rail_Ticket_Booking_M_Tbl)我得到了这个错误。Ms
在大多数情况下,我可以通过ORDER BY CASE WHEN myCol is null then 0 else 1 end DESC, myCol ASC很好地完成这项工作 但是我遇到了一种特定的场景请考虑以下内容: Select 'b' as wordselect null as wordselect 'a' as word
ORDER BY如果我应用下面的逻辑,我会得到一个错误: Se