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Leetcode 347. Top K Frequent Elements

版权声明:博客文章都是作者辛苦整理的,转载请注明出处,谢谢! https://cloud.tencent.com/developer/article/1435031

文章作者:Tyan

博客:noahsnail.com | CSDN | 简书

1. Description

2. Solution

  • Version 1
代码语言:javascript
复制
bool compare(const pair<int, int> &a, const pair<int, int> &b) {
    return a.second > b.second;
}

class Solution {
public:
    vector<int> topKFrequent(vector<int>& nums, int k) {
        map<int, int> elements;
        for(int i = 0; i < nums.size(); i++) {
            elements[nums[i]]++;
        }
        vector<pair<int, int>> temp;
        map<int, int>::iterator iter;
        for(iter = elements.begin(); iter != elements.end(); iter++) {
            temp.push_back(pair<int, int>(iter->first, iter->second));
        }
        sort(temp.begin(), temp.end(), compare);
        vector<int> result;
        for(int i = 0; i < k; i++) {
            result.push_back(temp[i].first);
        }
        return result;
    }

};
  • Version 2
代码语言:javascript
复制
class Solution {
public:
    vector<int> topKFrequent(vector<int>& nums, int k) {
        map<int, int> elements;
        for(int i = 0; i < nums.size(); i++) {
            elements[nums[i]]++;
        }
        vector<vector<int>> bucket(nums.size() + 1);
        map<int, int>::iterator iter;
        for(iter = elements.begin(); iter != elements.end(); iter++) {
            bucket[iter->second].push_back(iter->first);
        }
        reverse(bucket.begin(), bucket.end());
        vector<int> result;
        for(int i = 0; i < bucket.size(); i++) {
            for(int j = 0; j < bucket[i].size(); j++) {
                result.push_back(bucket[i][j]);
                if(result.size() == k) {
                    return result;
                }
            }
        }
        return result;
    }

};

Reference

  1. https://leetcode.com/problems/top-k-frequent-elements/description/
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