std::log10(std::complex)
Defined in header <complex> | | |
|---|---|---|
template< class T > complex<T> log10( const complex<T>& z ); | | |
计算复杂的公共%28碱基10复值的%29对数z在负实轴上有一个分支。
此函数的行为等价于std::log(z)/std::log(10)...
参数
z | - | complex value |
|---|
返回值
复公对数z...
例
二次
#include <iostream>
#include <cmath>
#include <complex>
int main()
{
std::complex<double> z(0, 1); // // r = 0, = pi/2
std::cout << "2*log10" << z << " = " << 2.*std::log10(z) << '\n';
std::complex<double> z2(sqrt(2)/2, sqrt(2)/2); // r = 1, # = pi/4
std::cout << "4*log10" << z2 << " = " << 4.*std::log10(z2) << '\n';
std::complex<double> z3(-100, 0); // r = 100, # = pi
std::cout << "log10" << z3 << " = " << std::log10(z3) << '\n';
std::complex<double> z4(-100, -0.0); // the other side of the cut
std::cout << "log10" << z4 << " (the other side of the cut) = "
<< std::log10(z4) << '\n'
<< "(note: pi/log(10) = " << acos(-1)/log(10) << ")\n";
}二次
产出：
二次
2*log10(0,1) = (0,1.36438)
4*log10(0.707107,0.707107) = (0,1.36438)
log10(-100,0) = (2,1.36438)
log10(-100,-0) (the other side of the cut) = (2,-1.36438)
(note: pi/log(10) = 1.36438)二次
另见
log(std::complex) | complex natural logarithm with the branch cuts along the negative real axis (function template) |
|---|---|
log10 | computes common (base 10) logarithm (log10(x)) (function) |
log10(std::valarray) | applies the function std::log10 to each element of valarray (function template) |
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