交换变量
x = 6y = 5x, y = y, xprint x>>> 5print y>>> 6
if 语句在行内
print "Hello" if True else "World">>> Hello
连接
下面的最后一种方式在绑定两个不同类型的对象时显得很酷。
nfc = ["Packers", "49ers"]afc = ["Ravens", "Patriots"]print nfc + afc>>> ['Packers', '49ers', 'Ravens', 'Patriots']print str(1) + " world">>> 1 worldprint `1` + " world">>> 1 worldprint 1, "world">>> 1 worldprint nfc, 1>>> ['Packers', '49ers'] 1
计算技巧
#向下取整print 5.0//2>>> 2# 2的5次方print 2**5>> 32
注意浮点数的除法
print .3/.1>>> 2.9999999999999996print .3//.1>>> 2.0
数值比较
x = 2if 3 > x > 1:
print x>>> 2if 1 < x > 0:
print x>>> 2
两个列表同时迭代
nfc = ["Packers", "49ers"]afc = ["Ravens", "Patriots"]for teama, teamb in zip(nfc, afc):
print teama + " vs. " + teamb>>> Packers vs. Ravens>>> 49ers vs. Patriots
带索引的列表迭代
teams = ["Packers", "49ers", "Ravens", "Patriots"]for index, team in enumerate(teams):
print index, team>>> 0 Packers>>> 1 49ers>>> 2 Ravens>>> 3 Patriots
列表推导
已知一个列表,刷选出偶数列表方法:
numbers = [1,2,3,4,5,6]even = []for number in numbers:
if number%2 == 0:
even.append(number)
用下面的代替
numbers = [1,2,3,4,5,6]even = [number for number in numbers if number%2 == 0]
字典推导
teams = ["Packers", "49ers", "Ravens", "Patriots"]print {key: value for value, key in enumerate(teams)}>>> {'49ers': 1, 'Ravens': 2, 'Patriots': 3, 'Packers': 0}
初始化列表的值
items = [0]*3print items>>> [0,0,0]
将列表转换成字符串
teams = ["Packers", "49ers", "Ravens", "Patriots"]print ", ".join(teams)>>> 'Packers, 49ers, Ravens, Patriots'
从字典中获取元素
不要用下列的方式
data = {'user': 1, 'name': 'Max', 'three': 4}try:
is_admin = data['admin']except KeyError:
is_admin = False
替换为
data = {'user': 1, 'name': 'Max', 'three': 4}is_admin = data.get('admin', False)
获取子列表
x = [1,2,3,4,5,6]#前3个print x[:3]>>> [1,2,3]#中间4个print x[1:5]>>> [2,3,4,5]#最后3个print x[-3:]>>> [4,5,6]#奇数项print x[::2]>>> [1,3,5]#偶数项print x[1::2]>>> [2,4,6]
60个字符解决FizzBuzz
前段时间Jeff Atwood 推广了一个简单的编程练习叫FizzBuzz,问题引用如下:
写一个程序,打印数字1到100,3的倍数打印“Fizz”来替换这个数,5的倍数打印“Buzz”,对于既是3的倍数又是5的倍数的数字打印“FizzBuzz”。
这里有一个简短的方法解决这个问题:
for x in range(101):print"fizz"[x%3*4::]+"buzz"[x%5*4::]or x
集合
用到Counter
库
from collections import Counterprint Counter("hello")>>> Counter({'l': 2, 'h': 1, 'e': 1, 'o': 1})
迭代工具
和collections
库一样,还有一个库叫itertools
from itertools import combinations
teams = ["Packers", "49ers", "Ravens", "Patriots"]for game in combinations(teams, 2):
print game>>> ('Packers', '49ers')>>> ('Packers', 'Ravens')>>> ('Packers', 'Patriots')>>> ('49ers', 'Ravens')>>> ('49ers', 'Patriots')>>> ('Ravens', 'Patriots')
在python中,True
和False
是全局变量,因此:
False = Trueif False:
print "Hello"else:
print "World">>> Hello