问根据模板函数直接定义非模板函数

EN

// some template function
template <typename T>
void foo(T t) {...}

// I would like int_foo to behave like a regular function with
// foo<int> as its implementation (obviously this doesn't compile because
// using cannot be used like this)
using int_foo = foo<int>;

void int_foo(int i) {
    foo<int>(i);
}