从C#中的类生成包含重复节点的XML

using System;
using System.IO;
using System.Xml.Serialization;

// 定义一个包含重复节点的类
public class MyClass
{
    public string Name { get; set; }
    public int Age { get; set; }
}

class Program
{
    static void Main(string[] args)
    {
        // 创建一个包含重复节点的对象列表
        var myList = new List<MyClass>
        {
            new MyClass { Name = "Alice", Age = 25 },
            new MyClass { Name = "Bob", Age = 30 },
            new MyClass { Name = "Alice", Age = 35 }
        };

        // 创建XmlSerializer对象
        XmlSerializer serializer = new XmlSerializer(typeof(List<MyClass>));

        // 创建一个StringWriter来存储XML数据
        StringWriter stringWriter = new StringWriter();

        // 序列化对象并将结果存储在StringWriter中
        serializer.Serialize(stringWriter, myList);

        // 获取生成的XML字符串
        string xmlString = stringWriter.ToString();

        // 打印生成的XML字符串
        Console.WriteLine(xmlString);
    }
}

<ArrayOfMyClass>
    <MyClass>
        <Name>Alice</Name>
        <Age>25</Age>
    </MyClass>
    <MyClass>
        <Name>Bob</Name>
        <Age>30</Age>
    </MyClass>
    <MyClass>
        <Name>Alice</Name>
        <Age>35</Age>
    </MyClass>
</ArrayOfMyClass>