从JSON中提取深度嵌套的值

import json

def extract_value(json_data, target_key):
    if isinstance(json_data, dict):  # 判断是否为字典类型
        for key, value in json_data.items():
            if key == target_key:
                return value
            else:
                nested_value = extract_value(value, target_key)  # 递归调用
                if nested_value is not None:
                    return nested_value
    elif isinstance(json_data, list):  # 判断是否为列表类型
        for item in json_data:
            nested_value = extract_value(item, target_key)  # 递归调用
            if nested_value is not None:
                return nested_value
    return None

# 示例 JSON 数据
json_str = '''
{
    "name": "John",
    "age": 30,
    "address": {
        "street": "123 ABC St",
        "city": "XYZ",
        "country": "USA"
    },
    "books": [
        {
            "title": "Book 1",
            "author": "Author 1"
        },
        {
            "title": "Book 2",
            "author": "Author 2"
        }
    ]
}
'''

json_data = json.loads(json_str)

# 从 JSON 中提取深度嵌套的值
value = extract_value(json_data, "author")

print(value)  # 输出: Author 1