使用两个C++向量作为参数的“复杂”运算函数的最佳方法

#include <iostream>
#include <vector>

// 复杂运算函数，使用常量引用传递向量
std::vector<int> complexOperation(const std::vector<int>& vec1, const std::vector<int>& vec2) {
    if (vec1.size() != vec2.size()) {
        throw std::invalid_argument("Vectors must be of the same size");
    }

    std::vector<int> result;
    result.reserve(vec1.size());

    for (size_t i = 0; i < vec1.size(); ++i) {
        result.push_back(vec1[i] * vec2[i]); // 示例运算：元素相乘
    }

    return result;
}

int main() {
    std::vector<int> vec1 = {1, 2, 3};
    std::vector<int> vec2 = {4, 5, 6};

    try {
        std::vector<int> result = complexOperation(vec1, vec2);

        for (const auto& val : result) {
            std::cout << val << " ";
        }
    } catch (const std::exception& e) {
        std::cerr << "Error: " << e.what() << std::endl;
    }

    return 0;
}