使用python 3的直线上的最大点数

def maxPoints(points):
    if len(points) < 3:
        return len(points)
    
    max_count = 0
    
    for i in range(len(points)):
        slopes = {}
        same_points = 0
        for j in range(i+1, len(points)):
            dx = points[j][0] - points[i][0]
            dy = points[j][1] - points[i][1]
            
            if dx == 0 and dy == 0:
                same_points += 1
                continue
            
            if dx == 0:
                slope = float('inf')
            else:
                slope = dy / dx
            
            intercept = points[i][1] - slope * points[i][0]
            
            if (slope, intercept) in slopes:
                slopes[(slope, intercept)] += 1
            else:
                slopes[(slope, intercept)] = 1
        
        max_count = max(max_count, max(slopes.values()) + same_points + 1)
    
    return max_count