具有一个函数的列表的嵌套字典的顶级长度

nested_dict = {
    "module1": [func1, func2],
    "module2": [func3, func4, func5],
    "module3": [func6]
}

length = len(nested_dict)
print(length)  # 输出：3

try:
    print(nested_dict["module4"])
except KeyError:
    print("Key 'module4' not found")

# 定义一些示例函数
def func1():
    return "Function 1"

def func2():
    return "Function 2"

def func3():
    return "Function 3"

# 创建嵌套字典
nested_dict = {
    "module1": [func1, func2],
    "module2": [func3]
}

# 获取顶级长度
length = len(nested_dict)
print(f"Top-level length: {length}")

# 访问存在的键
if "module1" in nested_dict:
    for func in nested_dict["module1"]:
        print(func())

# 访问不存在的键
if "module3" not in nested_dict:
    print("Key 'module3' not found")