我需要group by id并选择最小/最大seq为start和end的task id | task | seq 1 | aaa | 1CASE WHEN seq = MIN(seq) THEN task AS start,FROM table
GROUPBY id; 但这会导致 ERROR: column "seq" must appear in the
有一种奇怪的行为。我知道在使用GROUP时,SELECT中的所有列都应该在group子句中,或者具有聚合函数。然而,下一段代码显示了一些有争议的内容:select id, name from user group by name; <-- error becauseof group by (expected)
select id, name f
该节的问题11问:“每一场涉及'POL‘的比赛,都要显示出比赛情况、日期和进球数。”matchid, mdate, COUNT(player)WHERE (team1 = 'POL' OR team2 = 'POL')FROM goal JOIN game ON matchid = id
WHERE (team1 = 'POL