我有一个类似的语料库,格式如下:
parallel_corpus =
one sentence in Italian : one sentence in English
one sentence in Italian : one sentence in English
我有一个这种格式的双语术语列表
bigram_list =
Difensori dei diritti umani, libertà di espressione > Human rights defenders, freedom of expression
sgomberi forzati, violazioni de
例如,如果我在一个字典中有数百万条记录,其形式为{(1,2):3,(2,3):4,(3:2):5...xmillion},这是一个作为关键字的元组,并具有相应的值
我想要做的是获得tuple1 =2的数据,我的一种方法是
for item, value in dict.iteritems():
if item[1] == 2:
Do operations here...
这是一种很慢的方法,有没有更好的算法来让它变得更快?就像..。这样我就不用重复上百万个项目了
我在python中使用NetworkX进行网络分析.我确定每个边的权重,并以下列方式将该边添加到图中:
import matplotlib.pyplot as plt
import networkx as nx
import numpy as np
airports = ['ATL','LAX','ORD']
weights = [500,200,150] #Note that in my real code I I calculated these weights, they are not provided
G = nx.Graph()
我正在尝试让我的代码从分数列表中打印出“来自(具有最低分数的国家)的法官的最低分数”。
到目前为止,我的代码如下:
print("ASSIGNMENT 02B - Olympic Scores\n")
print("This program prompts the user to enter seven scores\nbetween 0.0 and 10.0 from seven different national judges.\nThe program will determine the high and low scores along\nwith whic
好吧,我在努力学习haskell。有几次我贴出了被否决的问题,因为我不能很好地解释我想要达到的目标,但是我要用一个新的问题再试一次。
我找到了一段我想要修改的代码。下面是:
import qualified Data.Map as M
type Dict = M.Map String String
translate :: Dict -> [String] -> [String]
translate dict words = map trans words
where
trans :: String -> String
trans w =