在函数返回时中断循环

def find_number(numbers, target):
    for num in numbers:
        if num == target:
            return True  # 在函数返回时中断循环
    return False

numbers = [1, 2, 3, 4, 5]
target = 3
result = find_number(numbers, target)
print(result)  # 输出：True

class BreakLoopException extends Exception {
    // 自定义异常类
}

boolean findNumber(int[] numbers, int target) {
    for (int num : numbers) {
        if (num == target) {
            try {
                throw new BreakLoopException();  // 在函数返回时中断循环
            } catch (BreakLoopException e) {
                return true;
            }
        }
    }
    return false;
}

public static void main(String[] args) {
    int[] numbers = {1, 2, 3, 4, 5};
    int target = 3;
    boolean result = findNumber(numbers, target);
    System.out.println(result);  // 输出：true
}