在标识符的值内，将重叠的日期时间间隔拆分为非重叠的间隔

from datetime import datetime

def merge_intervals(intervals):
    if not intervals:
        return []

    # 按照区间的起始时间排序
    intervals.sort(key=lambda x: x[0])

    merged = []
    current_interval = intervals[0]

    for interval in intervals[1:]:
        # 如果当前区间和下一个区间重叠
        if current_interval[1] >= interval[0]:
            # 合并区间
            current_interval[1] = max(current_interval[1], interval[1])
        else:
            # 不重叠，将当前区间加入结果列表
            merged.append(current_interval)
            current_interval = interval

    # 加入最后一个区间
    merged.append(current_interval)

    return merged

# 示例输入
intervals = [
    [datetime(2023, 10, 1, 9, 0), datetime(2023, 10, 1, 11, 0)],
    [datetime(2023, 10, 1, 10, 0), datetime(2023, 10, 1, 12, 0)],
    [datetime(2023, 10, 1, 14, 0), datetime(2023, 10, 1, 15, 0)]
]

# 处理重叠区间
merged_intervals = merge_intervals(intervals)

# 输出结果
for interval in merged_intervals:
    print(f"[{interval[0]}, {interval[1]}]")