在SwiftUI iOS中获得openurl后，如何关闭SFSafariviewcontroller？

safariViewController.delegate = self

func safariViewControllerDidFinish(_ controller: SFSafariViewController) {
    controller.dismiss(animated: true, completion: nil)
}

import SwiftUI
import SafariServices

struct ContentView: View {
    @State private var showSafari = false
    
    var body: some View {
        Button(action: {
            showSafari = true
        }) {
            Text("打开Safari")
        }
        .sheet(isPresented: $showSafari) {
            SafariView(url: URL(string: "https://www.example.com")!)
        }
    }
}

struct SafariView: UIViewControllerRepresentable {
    let url: URL
    
    func makeUIViewController(context: Context) -> SFSafariViewController {
        let safariViewController = SFSafariViewController(url: url)
        safariViewController.delegate = context.coordinator
        return safariViewController
    }
    
    func updateUIViewController(_ uiViewController: SFSafariViewController, context: Context) {
        // 更新视图控制器
    }
    
    func makeCoordinator() -> Coordinator {
        Coordinator(self)
    }
    
    class Coordinator: NSObject, SFSafariViewControllerDelegate {
        let parent: SafariView
        
        init(_ parent: SafariView) {
            self.parent = parent
        }
        
        func safariViewControllerDidFinish(_ controller: SFSafariViewController) {
            controller.dismiss(animated: true, completion: nil)
        }
    }
}