在c ++中解析argc和argv

#include<iostream>

int main(int argc, char *argv[]) {
    std::cout << "This program has "<< argc << " arguments."<< std::endl;
    std::cout << "The arguments are:"<< std::endl;
    for (int i = 0; i < argc; ++i) {
        std::cout << "argv[" << i << "] = "<< argv[i]<< std::endl;
    }
    return 0;
}