在restTemplate.exchange中，XML响应会自动解组吗？

import org.springframework.http.HttpMethod;
import org.springframework.http.ResponseEntity;
import org.springframework.web.client.RequestCallback;
import org.springframework.web.client.ResponseExtractor;
import org.springframework.web.client.RestTemplate;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import java.io.StringReader;

public class XmlResponseExample {
    public static void main(String[] args) {
        RestTemplate restTemplate = new RestTemplate();

        // 发送请求并接收XML响应
        ResponseEntity<String> response = restTemplate.exchange("http://example.com/api", HttpMethod.GET, null, String.class);

        // 解析XML响应为对象
        MyObject myObject = parseXmlResponse(response.getBody(), MyObject.class);

        // 使用解析后的对象进行后续操作
        // ...
    }

    private static <T> T parseXmlResponse(String xml, Class<T> clazz) {
        try {
            JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
            Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();
            return (T) unmarshaller.unmarshal(new StringReader(xml));
        } catch (JAXBException e) {
            e.printStackTrace();
            return null;
        }
    }

    // 定义需要解析的对象结构
    // ...
}