>>> sin(x).series(x,1,n=3)
sin(1) + (x - 1)*cos(1) - (x - 1)**2*sin(1)/2 + O((x - 1)**3, (x, 1))
极限的方向也是用...>>>f = Function('f')
>>> diffeq = Eq(f(x).diff(x, x) - 2*f(x).diff(x) + f(x), sin(x))
>>> dsolve(diffeq...(n, 1, +oo)) # 仅当r>1时 收敛
Piecewise((zeta(r), r > 1), (Sum(n**(-r), (n, 1, oo)), True))
拉普拉斯变换
?...>>> from sympy.integrals.transforms import inverse_laplace_transform
>>> from sympy import exp, Symbol...>>> from sympy import fourier_transform, exp
>>> from sympy.abc import x, k
>>> fourier_transform(exp