如何使值为90后的子串+1

def increment_90s_substrings(string):
    result = ""
    i = 0
    while i < len(string):
        if string[i:i+2] == "90":
            # 找到值为90后的子串
            j = i + 2
            while j < len(string) and string[j].isdigit():
                j += 1
            # 将子串转换为整数并加1
            num = int(string[i:j]) + 1
            # 将加1后的整数转换回字符串
            result += str(num)
            i = j
        else:
            result += string[i]
            i += 1
    return result

# 示例调用
string = "abc90def9090ghi90jkl"
result = increment_90s_substrings(string)
print(result)