如何使用C++/winrt声明Midi输入处理程序？

#include <winrt/Windows.Devices.Midi.h>
using namespace winrt::Windows::Devices::Midi;

MidiInPort midiInPort = MidiInPort::FromIdAsync(midiDeviceId).get();

midiInPort.MessageReceived({ this, &MyClass::OnMidiMessageReceived });

void MyClass::OnMidiMessageReceived(MidiInPort sender, MidiMessageReceivedEventArgs args)
{
    // 处理接收到的MIDI消息
    MidiMessage message = args.Message();
    // ...
}

midiInPort.Start();

#include <winrt/Windows.Devices.Midi.h>
using namespace winrt::Windows::Devices::Midi;

class MyClass
{
public:
    void InitializeMidiInput()
    {
        // 初始化MIDI输入设备
        MidiInPort midiInPort = MidiInPort::FromIdAsync(midiDeviceId).get();

        // 注册MIDI输入事件处理程序
        midiInPort.MessageReceived({ this, &MyClass::OnMidiMessageReceived });

        // 启动MIDI输入监听
        midiInPort.Start();
    }

private:
    void OnMidiMessageReceived(MidiInPort sender, MidiMessageReceivedEventArgs args)
    {
        // 处理接收到的MIDI消息
        MidiMessage message = args.Message();
        // ...
    }

    // 其他成员变量和方法
};

int main()
{
    MyClass myObject;
    myObject.InitializeMidiInput();

    // 其他逻辑

    return 0;
}