如何使用arccos函数找到范围从0 rad到2 rad的两个矢量之间的角度，而不是内角

import math

def vector_angle(v1, v2):
    dot_product = sum(a * b for a, b in zip(v1, v2))
    magnitude_v1 = math.sqrt(sum(a**2 for a in v1))
    magnitude_v2 = math.sqrt(sum(b**2 for b in v2))
    
    cos_theta = dot_product / (magnitude_v1 * magnitude_v2)
    
    # 确保cos_theta在[-1, 1]范围内，以避免arccos的域错误
    cos_theta = max(min(cos_theta, 1.0), -1.0)
    
    theta = math.acos(cos_theta)
    
    # 如果点积为负，则调整角度范围
    if dot_product < 0:
        theta += math.pi
    
    return theta

# 示例向量
v1 = [1, 0]
v2 = [-1, 1]

angle = vector_angle(v1, v2)
print(f"The angle between the vectors is {angle} radians.")