如何使用dataframe one column来匹配dict值以获取dict key

column_list = df['column_name'].tolist()

matching_keys = []
for value in column_list:
    for key, val in my_dict.items():
        if val == value:
            matching_keys.append(key)
            break

import pandas as pd

# 创建示例dataframe和字典
data = {'column_name': ['value1', 'value2', 'value3']}
df = pd.DataFrame(data)

my_dict = {'key1': 'value1', 'key2': 'value2', 'key3': 'value3'}

# 将dataframe列转换为列表
column_list = df['column_name'].tolist()

# 匹配字典值并获取对应的键
matching_keys = []
for value in column_list:
    for key, val in my_dict.items():
        if val == value:
            matching_keys.append(key)
            break

# 打印匹配的键
print(matching_keys)