如何在一定数量的字符在Python中出现超过一次后裁剪字符串？

def crop_string_after_char_appear_twice(input_string, char_to_count):
    # 计算字符出现的次数
    count = input_string.count(char_to_count)
    
    # 如果字符出现超过一次
    if count > 1:
        # 找到第二次出现的位置并裁剪字符串
        second_occurrence_index = input_string.find(char_to_count, input_string.find(char_to_count) + 1)
        return input_string[:second_occurrence_index]
    else:
        # 如果字符出现不超过一次，返回原始字符串
        return input_string

# 示例使用
original_string = "hello world, this is a test string with more than one t."
char_to_look_for = "t"
cropped_string = crop_string_after_char_appear_twice(original_string, char_to_look_for)
print(cropped_string)  # 输出: "hello worl"