如何在函数中使用结构类型来计算时间？

struct Time {
    int hours;
    int minutes;
    int seconds;
};

struct Time currentTime;
currentTime.hours = 10;
currentTime.minutes = 30;
currentTime.seconds = 45;

struct Time addTime(struct Time t1, struct Time t2) {
    struct Time result;
    result.hours = t1.hours + t2.hours;
    result.minutes = t1.minutes + t2.minutes;
    result.seconds = t1.seconds + t2.seconds;

    // 处理进位
    result.minutes += result.seconds / 60;
    result.seconds %= 60;
    result.hours += result.minutes / 60;
    result.minutes %= 60;

    return result;
}

int main() {
    struct Time t1, t2, sum;
    t1.hours = 5;
    t1.minutes = 45;
    t1.seconds = 30;

    t2.hours = 3;
    t2.minutes = 20;
    t2.seconds = 15;

    sum = addTime(t1, t2);

    printf("Sum of times: %02d:%02d:%02d\n", sum.hours, sum.minutes, sum.seconds);

    return 0;
}