如何将argv [1]传递给一个带0个参数的函数？

#include<iostream>

void myFunction(int arg) {
    std::cout << "The argument passed is: "<< arg<< std::endl;
}

int main(int argc, char *argv[]) {
    if (argc > 1) {
        int arg = atoi(argv[1]);
        myFunction(arg);
    } else {
        std::cout << "No argument passed."<< std::endl;
    }
    return 0;
}