如果id重复，则使用xslt更改重复的id。

<root>
  <item id="1">Item 1</item>
  <item id="2">Item 2</item>
  <item id="1">Duplicate Item 1</item>
</root>

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

  <xsl:output method="xml" indent="yes"/>

  <!-- Identity template to copy elements by default -->
  <xsl:template match="@*|node()">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
  </xsl:template>

  <!-- Template to handle duplicate IDs -->
  <xsl:template match="item">
    <xsl:variable name="new-id" select="concat(@id, '_', position())"/>
    <item id="{$new-id}">
      <xsl:apply-templates select="@*|node()"/>
    </item>
  </xsl:template>

</xsl:stylesheet>

<root>
  <item id="1">Item 1</item>
  <item id="2">Item 2</item>
  <item id="1_3">Duplicate Item 1</item>
</root>