寻找一种将字符串转换为日志级别的有效方法

function getLogLevelFromString(levelString) {
  switch (levelString.toLowerCase()) {
    case 'debug':
      return LogLevel.DEBUG;
    case 'info':
      return LogLevel.INFO;
    case 'warn':
      return LogLevel.WARN;
    case 'error':
      return LogLevel.ERROR;
    default:
      throw new Error('Invalid log level: ' + levelString);
  }
}

// 使用示例
const logLevelString = 'debug';
const logLevel = getLogLevelFromString(logLevelString);
console.log(logLevel); // 输出：LogLevel.DEBUG

import logging

def get_log_level_from_string(level_string):
    if level_string.lower() == 'debug':
        return logging.DEBUG
    elif level_string.lower() == 'info':
        return logging.INFO
    elif level_string.lower() == 'warn':
        return logging.WARNING
    elif level_string.lower() == 'error':
        return logging.ERROR
    else:
        raise ValueError('Invalid log level: ' + level_string)

# 使用示例
log_level_string = 'debug'
log_level = get_log_level_from_string(log_level_string)
print(log_level)  # 输出：10 (对应 logging.DEBUG)