当list停止增加Python时返回索引

def find_index_stop_adding(lst, stop_value):
    for i in range(len(lst)):
        if lst[i] == stop_value:
            return i
    return -1  # 如果列表中没有停止增加的元素，则返回-1

# 示例用法
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 10]
stop_value = 10
index = find_index_stop_adding(my_list, stop_value)
print(index)  # 输出：9

def find_index_stop_adding(lst, stop_value):
    try:
        index = lst.index(stop_value)
        return index
    except ValueError:
        return -1  # 如果列表中没有停止增加的元素，则返回-1

# 示例用法
my_list = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 10, 10, 10, 10]
stop_value = 10
index = find_index_stop_adding(my_list, stop_value)
print(index)  # 输出：9