找出可以表示为数组中三个不同元素之和的所有数字

def threeSum(nums):
    nums.sort()  # 排序数组
    result = []
    n = len(nums)
    
    for i in range(n-2):
        if i > 0 and nums[i] == nums[i-1]:  # 跳过重复的元素
            continue
        
        j = i + 1
        k = n - 1
        
        while j < k:
            if nums[i] + nums[j] + nums[k] == 0:
                result.append([nums[i], nums[j], nums[k]])
                j += 1
                k -= 1
                
                while j < k and nums[j] == nums[j-1]:  # 跳过重复的元素
                    j += 1
                while j < k and nums[k] == nums[k+1]:  # 跳过重复的元素
                    k -= 1
            elif nums[i] + nums[j] + nums[k] < 0:
                j += 1
            else:
                k -= 1
    
    return result