有没有办法找出在另一个函数的列表理解中调用了什么函数？

import inspect
import re

def find_called_functions(func):
    # 获取函数的源代码
    source_lines = inspect.getsource(func).splitlines()
    source_code = '\n'.join(source_lines)

    # 匹配列表理解的语句
    pattern = r'\[.*?\]'
    matches = re.findall(pattern, source_code)

    called_functions = set()

    for match in matches:
        # 解析列表理解语句，找出其中的函数调用
        function_calls = re.findall(r'\w+\(', match)
        called_functions.update(function_calls)

    return list(called_functions)

# 示例函数
def my_function():
    result = [some_func(x) for x in range(10)]
    return result

def some_func(x):
    return x + 1

# 调用示例函数
result = my_function()

# 找出调用了哪些函数
called_functions = find_called_functions(my_function)
print(called_functions)

['some_func(']