根据UIPicker位置动态调整UILabel x值？

import UIKit

class ViewController: UIViewController, UIPickerViewDelegate, UIPickerViewDataSource {
    
    let pickerView = UIPickerView()
    let label = UILabel()
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        // 设置UIPickerView的代理和数据源
        pickerView.delegate = self
        pickerView.dataSource = self
        
        // 设置UILabel的初始位置
        label.frame = CGRect(x: 0, y: 100, width: 200, height: 30)
        label.text = "Label"
        label.textAlignment = .center
        view.addSubview(label)
        
        // 将UIPickerView添加到视图中
        view.addSubview(pickerView)
    }
    
    // UIPickerViewDataSource方法：返回选择器的列数
    func numberOfComponents(in pickerView: UIPickerView) -> Int {
        return 1
    }
    
    // UIPickerViewDataSource方法：返回选择器的行数
    func pickerView(_ pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        return 5
    }
    
    // UIPickerViewDelegate方法：返回选择器的每一行的标题
    func pickerView(_ pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        return "Option \(row)"
    }
    
    // UIPickerViewDelegate方法：选择器选中项发生变化时调用
    func pickerView(_ pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
        // 根据选中项的位置动态调整UILabel的x值
        let newX = CGFloat(row * 50)
        label.frame.origin.x = newX
    }
}