C# -获取列表中倒数第二项

using System;
using System.Collections.Generic;
using System.Linq;

public class Program
{
    public static void Main()
    {
        List<int> numbers = new List<int> { 1, 2, 3, 4, 5 };
        
        if (numbers.Count >= 2)
        {
            int secondLastItem = numbers.Skip(numbers.Count - 2).First();
            Console.WriteLine("倒数第二项是: " + secondLastItem);
        }
        else
        {
            Console.WriteLine("列表中没有足够的元素");
        }
    }
}

using System;
using System.Collections.Generic;

public class Program
{
    public static void Main()
    {
        List<int> numbers = new List<int> { 1, 2, 3, 4, 5 };
        
        if (numbers.Count >= 2)
        {
            int secondLastItem = numbers[numbers.Count - 2];
            Console.WriteLine("倒数第二项是: " + secondLastItem);
        }
        else
        {
            Console.WriteLine("列表中没有足够的元素");
        }
    }
}

using System;
using System.Collections.Generic;

public class Program
{
    public static void Main()
    {
        List<int> numbers = new List<int> { 1, 2, 3, 4, 5 };
        
        if (numbers.Count >= 2)
        {
            int lastItem = numbers[numbers.Count - 1];
            for (int i = numbers.Count - 2; i >= 0; i--)
            {
                if (numbers[i] != lastItem)
                {
                    Console.WriteLine("倒数第二项是: " + numbers[i]);
                    break;
                }
            }
        }
        else
        {
            Console.WriteLine("列表中没有足够的元素");
        }
    }
}